Antenna Length & Wavelength

Wavelength λ = c/f plus half-wave dipole and quarter-wave whip lengths, with velocity factor and end-effect correction.

Edit f or λ — the other follows. VF ≈ 0.95 for insulated wire; k ≈ 0.95 trims the dipole for end effects.

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Dipole and whip lengths

From frequency to antenna length

An electromagnetic wave travels at the speed of light, so its wavelength is just light speed divided by frequency. In a real conductor or coating the wave slows down by the velocity factor:

A resonant element is a fraction of that wavelength. Real metal rods radiate as if slightly longer than they are (the end effect), so we shorten the physical length by a factor :

This is why a half-wave dipole is a touch shorter than the electrical λ/2. A quick field shortcut in metres is for the full dipole, which lands within a centimetre of the exact formula across the HF and VHF bands.

Frequently asked questions

How do I calculate antenna length from frequency?

First find the wavelength λ = c / f with c = 299,792,458 m/s, then take a fraction of it. A half-wave dipole is k·λ/2 and a quarter-wave whip is k·λ/4, where k ≈ 0.95 trims for end effects. At 100 MHz, λ = 2.998 m, so the dipole is 0.95 × 2.998 / 2 ≈ 1.424 m.

What is the wavelength formula?

Wavelength equals the speed of light divided by frequency: λ = c / f, where c = 299,792,458 m/s. In a cable or coated element multiply by the velocity factor: λ = c·VF / f. For 2.4 GHz in free space, λ = 299,792,458 / 2.4e9 ≈ 0.125 m (12.5 cm).

How long is a half-wave dipole?

A half-wave dipole is about k·λ/2 with k ≈ 0.95 to account for the end effect, slightly shorter than the electrical λ/2. A handy shortcut in metres is L ≈ 143 / f(MHz). At 100 MHz that's 143 / 100 = 1.43 m, matching 0.95 × 2.998 / 2 ≈ 1.424 m.

What is velocity factor?

Velocity factor (VF) is how much slower a wave travels in a medium versus free space, from 0 to 1. It shortens the wavelength: λ = c·VF / f. Bare wire is near 1.0, insulated wire about 0.95, and coax typically 0.66–0.85, so resonant lengths shrink by that same factor.